5^x=(1/25)^(x-3)

Solution for 5^x=(1/25)^(x-3) equation:

5^x=(1/25)^(x-3)

We move all terms to the left:

5^x-((1/25)^(x-3))=0


Domain of the equation: 25)^(x-3))!=0

x∈R


We add all the numbers together, and all the variables

5^x-((+1/25)^(x-3))=0

We multiply all the terms by the denominator


5^x*25)^(x+1-3))-((=0

We add all the numbers together, and all the variables

5^x*25)^(x-2))-((=0

We add all the numbers together, and all the variables

5^x*25)^(x=0

Wy multiply elements

125x^2=0

a = 125; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·125·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{250}=0$